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Oracle Java Programming Certification Questions and Answers (Dumps and Practice Questions)



Question : Given the code fragment:

What is the result?
: Given the code fragment:
1. Execution terminates in the first catch statement, and caught a RuntimeException is printed to the console
2. Execution terminates In the second catch statement, and caught an Exception is printed to the console.
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4. Execution completes normally, and "Ready to use" is printed to the console.
5. The code fails to compile because a throws keyword is required.




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Explanation: After running the program below error will be printed. Reason : there is a infinite while loop while(true), which keeps adding a String object in List and never exit. Which causes this error.

Exception in thread "main" java.lang.outofMemoryError: Java heap space
at java.util.Arrays.copyof(Arrays.java:3210)
at java.util.Arrays.copyof(Arrays.java:3181)
at java.util.ArrayList.grow(ArrayList.java:261)
at java.util.ArrayList.ensureExplicitCapacity(ArrayList.java:235)
at java.util.ArrayList.ensureCapacityInternal(ArrayList.java:227)
at java.util.ArrayList.add(ArrayList.java:458)
at Q45.main(Q45.java:11)
Java Result: 1




Question : When you run the given program, what would be printed.


: When you run the given program, what would be printed.
1. int sum is 30
float sum is 30.0
2. int sum is 30
double sum is 30.0
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double sum is 30.0
4. Integer sum is 30
flaot sum is 30.0

Correct answer: 2



Question : Which statement initializes a stringBuilder to a capacity of ?

: When you run the given program, what would be printed.
1. StringBuilder sb = new String ("128");
2. StringBuilder sb = StringBuilder.setCapacity (128);
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4. StringBuilder sb = new StringBuilder (128);




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Explanation: StringBuilder(int capacity)
Constructs a string builder with no characters in it and an initial capacity specified by the capacity argument.
Note: An instance of a StringBuilder is a mutable sequence of characters.
The principal operations on a StringBuilder are the append and insert methods, which are
overloaded so as to accept data of any type. Each effectively converts a given datum to a
string and then appends or inserts the characters of that string to the string builder. The
append method always adds these characters at the end of the builder; the insert method adds
the characters at a specified point.







Question : You have been given code as shown, what happen when you compile/run

: You have been given code as shown, what happen when you compile/run
1. It will print 10:20
2. It will print 0:20
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4. Compilation fails at line n1
5. Compilation fails at line n2

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Related Questions

Question : Given the code fragment:
String h1 = "Bob";
String h2 = new String ("Bob");
What is the best way to test that the values of h1 and h2 are the same?

 : Given the code fragment:
1. if (h1 = = h2)
2. if (h1.equals(h2))
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4. if (h1.same(h2))



Question : You have been given belwo interface declaration

interface Runnable {
public voide run();
}

Which of the following will create instance of Runnable type?

 : You have been given belwo interface declaration
1. Runnable run = 0 -> {
System.out.println("Run");
}
2. Runnable run = 0 -> System.out.println("Run");
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4. Runnable run => System.out.println("Run");
5. None of above





Question : You have been given below Java Code

public class Painting {
private String type;

public String getType() {
return type;
}

public void setType(String type) {
this.type = type;
}

public static void main(String[] args) {
Painting obj1 = new Painting();
Painting obj2 = new Painting();
obj1.setType(null);
obj2.setType("Fresco");
System.out.print(obj1.getType() + " : " + obj2.getType());
}
}

When you run it, what would be printed ?


 : You have been given below Java Code
1. : Fresco
2. null : Fresco
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4. A NullPointerException is thrown at runtime





Question : You have been given below code

boolean log3 = (5.0 != 6.0) && (4 != 5);
boolean log4 = (4 != 4) || (4 == 4);
System.out.println("\n log3:" + log3 + "\n log4 : " + log4);

When you execute this code, what would be printed ?
 : You have been given below code
1. log3:false
log4:true
2. log3:true
log4:true
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log4:false
4. log3:false
log4:false






Question : You have been given following code

public class Test {
static boolean bVar;

public static void main(String[] args) {
boolean bVar1 = true;
int count = 8;
do {
System.out.println("Hello Java! " + count);
if (count >= 7) {
bVar1 = false;
}
} while (bVar != bVar1 && count > 4);
count -= 2;
}
}

When you run it, what would be printed ?

 : You have been given following code
1. Hello Java! 8 Hello Java! 6 Hello Java! 4
2. Hello Java! 8 Hello Java! 6
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4. Compilation fails




Question : You have been given following code

public class TestLoop {
public static void main(String[] args) {
int array[] = { 0, 1, 2, 3, 4 };
int key = 3;
for (int pos = 0; pos < array.length; ++pos) {
if (array[pos] == key) {
break;
}
}
System.out.print("Found " + key + "at " + pos);
}
}

What is the result?

 : You have been given following code
1. Found 3 at 2
2. Found 3 at 3
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4. An exception is thrown at runtime