Oracle Advacned Java Advanced Certification Questions and Answers (Dumps and Practice Questions)
Question : You have been given below code. What is the behavior of the code?
package com.hadoopexam;
import java.util.function.Function;
public class Welcome {
public static void main(String[] args) {
Function
.compose(square);
System.out.println(negateSquare.apply(13));
}
}
1. Code will be having a compile time error.
2. Code will produce the output as -169
4. Code will produce output as 13
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Explanation: As you know , when you use compose for two functions, it will first call the function which is bracket like square. Hence, 13 will be squared to 169 first
and then it will be negated so result would be -169.
Question : You have been given a following method of Long class.
long parseLong(String s)
Now select the correct functional interface for which, you can pass method reference like.
Long::parseLong()
1. BiPredicate
2. Function
4. Predicate
5. Consumer
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Explanation: The parseLong() method takes a String and returns a value, So we need to use the Function interface because it matches the signature of the
abstract method R apply(T t). In Function
as the argument and returns a long (that can be wrapped in an Integer), we can assign it to Function
Question : You have been given below code, when you run this code. What would be the behavior?
package com.hadoopexam;
import java.util.function.BiFunction;
public class Welcome {
public static void main(String args[]) {
BiFunction
System.out.println(stringCompare.apply("HadoopExam", "HadoopExam"));
}
}
1. It will generate compile time error.
2. You cannot use predicate in Function interface. Hence, will generate RuntimeError
4. Program runs perfectly and produce false.
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Explanation: BiFunction has an apply() function which take two arguments as an input. So here stringCompare is defined for the same. We will be providing two
arguments as an input and one Boolean as an output. So this code works fine and produce the true as an output. Because both the strings are same.
Related Questions
Question : You have been given below code, what is the expected behavior?
package com.hadoopexam;
import java.util.Arrays;
import java.util.List;
import java.util.function.UnaryOperator;
public class Welcome {
public static void main(String[] args) {
UnaryOperator
List
dataList.stream().filter(value -> value >= 10).map(newValue -> doubleValue.apply(newValue))
.forEach(val1 -> System.out.print(val1 + " ")); //n2
}
}
1. 20 40 50
2. 110
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4. A compilation error occurs at line n2.
Question : You have been asked to create a ResourceBundle which uses a properties file to localize an application.
Which of the below example specifies valid keys and values ?
?
1.
2.
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4. menu1 = Exam Menu
menu2 = Paper Menu
Question : You have been given below code, select the correct statement which applies to it.
package com.hadoopexam;
import java.io.BufferedReader;
import java.io.DataInputStream;
import java.io.FileInputStream;
import java.io.IOException;
import java.io.InputStreamReader;
class Welcome {
public static void main(String[] args) throws IOException {
FileInputStream findings = new FileInputStream("HadoopExam.txt");
DataInputStream dataStream = new DataInputStream(findings);
BufferedReader br = new BufferedReader( new InputStreamReader(dataStream));
String line;
while ((line = br.readLine()) != null) {
System.out.println(line);
}
br.close();
}
}
1. br.close() statement will close only the BufferedReader object, and findings and dataStream will remain unclosed.
2. The br.close() statement will close the BufferedReader object and the underlying stream objects referred by findings and dataStream.
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collects all resources.
4. All of the above
Question : You have been given below code, what is the expected behavior ?
package com.hadoopexam;
import java.nio.file.*;
public class Welcome {
public static void main(String[] args) {
Path hePath = Paths.get("C:\\HadoopExam\\he1.txt");
while (hePath.iterator().hasNext()) {
System.out.println("Next Path: " + hePath.iterator().next());
}
}
}
1. It will give compile time error
2. It will give runtime error
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4. It will print only once "Next Path: C:\HadoopExam\he1.txt"
5. It will go in infinite loop.
Question : You have been given below path, what is the expected code behavior?
package com.hadoopexam;
import java.nio.file.Path;
import java.nio.file.Paths;
public class Welcome {
public static void main(String []args) {
Path path = Paths.get("D:\\HadoopExam\\HE\\..\\HE2\\com\\.\\Welcome.java");
path = path.normalize();
System.out.println(path.subpath(2, 3));
}
}
1. It gives compile time error
2. It will give runtime error
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4. It will print "HadoopExam"
5. It will print "com"
Question : You have been given below code, what is the expected behavior?
package com.hadoopexam;
import java.io.IOException;
import java.nio.file.Path;
import java.nio.file.Paths;
public class Welcome {
public static void main(String[] args) throws IOException {
Path path = Paths.get("C:\\HadoopExam\\he.txt");
System.out.println(path.isAbsolute());
}
}
1. Compile time error
2. Runtime exception
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4. It will print true
5. Depend on file exist or not