Oracle Advacned Java Advanced Certification Questions and Answers (Dumps and Practice Questions)
Question : You have been given the below code, what is the behavior you expect.
package com.hadoopexam;
import java.util.ArrayDeque;
import java.util.Arrays;
import java.util.Deque;
class Welcome {
public static void main(String[] args) {
Deque
deque.addAll(Arrays.asList(1, 2, 3, 4, 5));
System.out.println("First removed element is = " + deque.remove());
}
}
1. Code will through compile time exception.
2. Code will compile but through Runtime exception "IllegalStateException"
3. Code will compile and run perfectly and print First removed element is = 5
4. Code will compile and run perfectly and print First removed element is = 1
Correct Answer : Get Lastest Questions and Answer :
Explanation: As remove() method will remove the first element from Deque .
Question : You have been given below code. Select the correct behavior of the code.
package com.hadoopexam;
class Parent
private T test;
void call(T t) {
test = t;
System.out.println("Testing Method 1");
}
}
package com.hadoopexam;
class Welcome
public Welcome(S s) {
}
void call(S s) {
System.out.println("Testing Method 2");
}
}
package com.hadoopexam;
class Test {
public static void main(String[] args) {
Welcome
err.call("Calling");
}
}
1. Code will compile and run with the output as "Testing Method 2"
2. Code will compile and run with the output as "Testing Method 1"
4. Code will not compile because there is an ambiguity in code call method
Correct Answer : Get Lastest Questions and Answer :
Explanation: When code check compile time there are two methods defined call(S s) and call(T t). And no datatype is defined for them. Hence, compile will see signature of
the methods as call (String) and call(S extends CharSequence) and they would be considered as overloaded method and not overridden method. Having the same signature for overloaded
method it will through compile time exception considering the ambiguity.
Question : Select the correct functional interface from below.
A. java.util.stream.Stream
B. java.util.function.Consumer
C. java.util.function.Supplier
D. java.util.function.Predicate
E. java.util.function.Function
1. A,B,C
2. B,C,D
4. A,D,E
5. B,C,D,E
Correct Answer : Get Lastest Questions and Answer :
Explanation: The interface java.util.stream.Stream
numerous abstract methods. The other four options are functional interfaces.
The functional interface java.util.function.Consumer
with the signature void accept(T t);
The functional interface java.util.function.Supplier
with the signature T get();
The functional interface java.util.function.Predicate
with the signature boolean test(T t);
The functional interface java.util.function.Function
method with the signature R apply(T t);
Related Questions
Question : You have been given below code, what is the behavior expected?
package com.hadoopexam;
import java.nio.file.FileAlreadyExistsException;
class Welcome {
@SuppressWarnings("finally")
public static void call() throws Exception {
try {
throw new FileAlreadyExistsException(null);
} finally {
throw new Exception();
}
}
public static void main(String[] args) {
try {
call();
} catch (Throwable throwable) {
System.out.println(throwable);
}
}
}
1. It will not compile
2. It will compile and run with Throwable
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4. It will compile and run with no output
5. It will compile and run with FileAlreadyExistsException
Question : You have been given following code, what is the behavior expected
package com.hadoopexam;
import java.time.LocalDate;
import java.time.Month;
import java.time.Period;
class Welcome {
public static void main(String[] args) {
LocalDate date1 = LocalDate.of(2014, Month.MARCH, 01);
LocalDate date2 = LocalDate.of(2016, Month.NOVEMBER, 01);
System.out.println(Period.between(date2, date1).getYears());
}
}
1. It will give compile time error
2. It will compile and run perfectly and print 1
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4. It will compile and run perfectly and print -1
5. It will compile and run perfectly and print -2
Question : Which one of the following classes is best suited for storing timestamp values of application events in a file?
1. java.time.ZoneId class
2. java.time.ZoneOffset class
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4. java.time.Duration class
5. java.time.Period class
Question : You have been given below code, what is the expected behavior?
package com.hadoopexam;
import java.time.LocalDateTime;
import java.time.ZoneId;
import java.time.ZonedDateTime;
class Welcome {
public static void main(String[] args) {
ZoneId zoneId = ZoneId.of("Asia/Kolkata");
ZonedDateTime zonedDateTime = ZonedDateTime.of(LocalDateTime.now(), zoneId);
System.out.println(zonedDateTime.getOffset());
}
}
1. It will not compile.
2. It will compile and print +5:30[Asia/Kolkata]
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4. It will compile and print +5:30[UTC]
5. It will compile and print +5:30
Question : You have been given below code, what behavior is expected?
package com.hadoopexam;
import java.time.LocalDate;
import java.time.Month;
import java.time.format.DateTimeFormatter;
class Welcome {
public static void main(String[] args) {
DateTimeFormatter dateFormat = DateTimeFormatter.ISO_DATE;
LocalDate dateOfBirth = LocalDate.of(2016, Month.FEBRUARY, 29);
System.out.println(dateFormat.format(dateOfBirth));
}
}
1. It will give compile time error.
2. It will produce output as '2016-02-29'
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4. It will produce output as '2016-Feb-29'
Question : You have been given following code, and running from a system which are installed in India on Saturday and month is November and Year is . What will be the behavior
of the code?
package com.hadoopexam;
import java.time.LocalDateTime;
import java.time.format.DateTimeFormatter;
import java.util.Locale;
class Welcome {
public static void main(String[] args) {
DateTimeFormatter formatter = DateTimeFormatter.ofPattern("EEEE",Locale.US);
System.out.println(formatter.format(LocalDateTime.now()));
}
}
1. It will not compile.
2. It will print NOVEMBER
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4. It will print Satu.